Something that I get to do occasionally at work is review old code to fix some random bug. I actually enjoy doing this because I rarely get to program anymore (since I have never been a developer) and it’s nice to brush up on it again. The other day, I ran into some code I hadn’t seen before, that is valid Perl, but is much more C like:
return ($n < 0) ? 0 : $n;
The biggest problem with trying to figure out what this does if you’ve never seen it before is that you have no idea what to search for. Do you look up “?:”, no, because that actually means something else. Google Code Search has been my friend in the past on things like this, because it can handle all the special characters. I highly recommend trying it out. This time I figured out it was an old C construct, so I just went over and asked a developer what it meant.
So, for those who didn’t know already, this is what it means:
($n < 0) – this is the statement that is being checked (like in an if statement).
The part between the ? and the : is what is returned if the statement is true. The part after the : is what is returned if the statement is false.
So in this case, the author was making sure that the number returned was positive. If $n was less than zero (or negative), it would return zero. If it was zero or some positive number, it just returned that number.
Now, why would you do this? Well, it would all depend on how the variable was derived in the subroutine above it. In my case, the author was using a creative method to find the total number of a specific character in a string (in this case the slash):
my $str = shift(@_);
my $n = split('/', $str) - 1;
Now, although this works, Perl will complain about it because you are clobbering the array @_ and consequently your subroutine arguments. So I ended up changing the code to use the translate command “tr”, which returns the number of matches:
my $n = ($str =~ tr////);
Of course, now the return code is irrelevant, but not causing any harm…